Як розв’язувати показниковi рiвняння

$$\begin{array}{llll}\hfill x^2& =49& \hfill & \\ \hfill \sqrt{x^2}& =\sqrt{49}& \hfill & \\ \hfill x& =\pm 7& \hfill & \end{array}$$

$$\begin{array}{llll}\hfill 2x^2& =98& \hfill & \\ \hfill \frac{2x^2}{2}& =\frac{98}{2}& \hfill & \\ \hfill x^2& =49& \hfill & \\ \hfill \sqrt{x^2}& =\sqrt{49}& \hfill & \\ \hfill x& =\pm 7& \hfill & \end{array}$$